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atnikuffnen1977

Steinbergcubase75keygentorrent Ivorana







A: I've managed to get the output you want by doing a couple of things. Remove the quotes around the colon If you only want a single property, use the split command (but you will need to parse the result) You can use the JSON_QUERY function, which allows you to get multiple values at once (check out the documentation) This is the code: var f2 = new FileStream(path, FileMode.Open, FileAccess.Read); var result = JsonConvert.DeserializeObject(File.ReadAllText(path)); var entries = result.Children().Where(x => string.IsNullOrEmpty(x["key"].Value())).ToArray(); var size = entries.Length; var time = entries.Last().Values("creation_time").ToArray(); var name = entries.Last().Values("local_size").ToArray(); var d1 = new DateTime(name[0].ToString(), time[0].ToString(), 0); var year = d1.Year; var month = d1.Month; var day = d1.Day; var hour = d1.Hour; var minute = d1.Minute; var second = d1.Second; var hour1 = time[0].ToString().Substring(0,2); var minute1 = time[0].ToString().Substring(2,2); var second1 = time[0].ToString().Substring(4,2); var month1 = time[0].ToString().Substring(6,2); var day1 = time[0].ToString().Substring(8,2); var year1 = d1.Year; var month2 = year1.Substring(0,2); var day2 = year1.Substring(2,2); var hour2 = year1.Substring(4,2); var minute2 = year1.Substring(6,2); var second2 = year1.Substring(8,2); The last line, however, is superfluous. If you try to serialize an array, it will just serialize the array as an object. Side note: ac619d1d87


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